Finite strain theory

In continuum mechanics, the finite strain theory—also called large strain theory, or large deformation theory—deals with deformations in which strains and/or rotations are large enough to invalidate assumptions inherent in infinitesimal strain theory. In this case, the undeformed and deformed configurations of the continuum are significantly different, requiring a clear distinction between them. This is commonly the case with elastomers, plastically deforming materials and other fluids and biologicalsoft tissue.

Displacement field

Figure 1. Motion of a continuum body.

The displacement of a body has two components: a rigid-body displacement and a deformation.

  • A rigid-body displacement consists of a translation and rotation of the body without changing its shape or size.
  • Deformation implies the change in shape and/or size of the body from an initial or undeformed configuration κ0(B){\displaystyle \kappa _{0}({\mathcal {B}})} to a current or deformed configuration κt(B){\displaystyle \kappa _{t}({\mathcal {B}})} (Figure 1).

A change in the configuration of a continuum body can be described by a displacement field. A displacement field is a vector field of all displacement vectors for all particles in the body, which relates the deformed configuration with the undeformed configuration. The distance between any two particles changes if and only if deformation has occurred. If displacement occurs without deformation, then it is a rigid-body displacement.

Deformation gradient tensor

Figure 2. Deformation of a continuum body.

The deformation gradient tensor is a quantity related to both the reference and current configuration, and expresses motion locally around a point. Two types of deformation gradient tensor may be defined.

The material deformation gradient tensorF(X,t)=FjKejIK{\displaystyle \mathbf {F} (\mathbf {X} ,t)=F_{jK}\mathbf {e} _{j}\otimes \mathbf {I} _{K}} is a second-order tensor that represents the gradient of the smooth and invertible mapping function χ(X,t){\displaystyle \chi (\mathbf {X} ,t)\,\!}, which describes the motion of a continuum. In particular, the continuity of the mapping function χ(X,t){\displaystyle \chi (\mathbf {X} ,t)\,\!} implies that cracks and voids do not open or close during the deformation. The material deformation gradient tensor characterizes the local deformation at a material point with position vector X{\displaystyle \mathbf {X} \,\!}, i.e., deformation at neighbouring points, by transforming (linear transformation) a material line element emanating from that point from the reference configuration to the current or deformed configuration. Thus we have, dx=xXdXordxj=xjXKdXK=χ(X,t)dXordxj=FjKdXK.=F(X,t)dX{\displaystyle {\begin{aligned}d\mathbf {x} &={\frac {\partial \mathbf {x} }{\partial \mathbf {X} }}\,d\mathbf {X} \qquad &{\text{or}}&\qquad dx_{j}={\frac {\partial x_{j}}{\partial X_{K}}}\,dX_{K}\\&=\nabla \chi (\mathbf {X} ,t)\,d\mathbf {X} \qquad &{\text{or}}&\qquad dx_{j}=F_{jK}\,dX_{K}\,.\\&=\mathbf {F} (\mathbf {X} ,t)\,d\mathbf {X} \end{aligned}}}

Assuming that χ(X,t){\displaystyle \chi (\mathbf {X} ,t)\,\!} has a smooth inverse, F{\displaystyle \mathbf {F} } has the inverse H=F1=Xx{\displaystyle \mathbf {H} =\mathbf {F} ^{-1}={\frac {\partial \mathbf {X} }{\partial \mathbf {x} }}\,\!}, which is the spatial deformation gradient tensor. F{\displaystyle \mathbf {F} } being invertible is equivalent to detF0{\displaystyle {\text{det}}\mathbf {F} \neq 0}, which corresponds to the notion that the material cannot be infinitely compressed.

Relative displacement vector

Consider a particle or material pointP{\displaystyle P} with position vector X=XIII{\displaystyle \mathbf {X} =X_{I}\mathbf {I} _{I}} in the undeformed configuration (Figure 2). After a displacement of the body, the new position of the particle indicated by p{\displaystyle p} in the new configuration is given by the vector position x=xiei{\displaystyle \mathbf {x} =x_{i}\mathbf {e} _{i}\,\!}. The coordinate systems for the undeformed and deformed configuration can be superimposed for convenience.

Consider now a material point Q{\displaystyle Q} neighboring P{\displaystyle P\,\!}, with position vector X+ΔX=(XI+ΔXI)II{\displaystyle \mathbf {X} +\Delta \mathbf {X} =(X_{I}+\Delta X_{I})\mathbf {I} _{I}\,\!}. In the deformed configuration this particle has a new position q{\displaystyle q} given by the position vector x+Δx{\displaystyle \mathbf {x} +\Delta \mathbf {x} \,\!}. Assuming that the line segments ΔX{\displaystyle \Delta X} and Δx{\displaystyle \Delta \mathbf {x} } joining the particles P{\displaystyle P} and Q{\displaystyle Q} in both the undeformed and deformed configuration, respectively, to be very small, then we can express them as dX{\displaystyle d\mathbf {X} } and dx{\displaystyle d\mathbf {x} \,\!}. Thus from Figure 2 we have x=X+u(X),x+dx=X+dX+u(X+dX),and thereforedx=Xx+dX+u(X+dX)=dX+u(X+dX)u(X)=dX+du,{\displaystyle {\begin{aligned}\mathbf {x} &=\mathbf {X} +\mathbf {u} (\mathbf {X} ),\\\mathbf {x} +d\mathbf {x} &=\mathbf {X} +d\mathbf {X} +\mathbf {u} (\mathbf {X} +d\mathbf {X} ),\\{\text{and}}{\text{ therefore}}&\\d\mathbf {x} &=\mathbf {X} -\mathbf {x} +d\mathbf {X} +\mathbf {u} (\mathbf {X} +d\mathbf {X} )\\&=d\mathbf {X} +\mathbf {u} (\mathbf {X} +d\mathbf {X} )-\mathbf {u} (\mathbf {X} )\\&=d\mathbf {X} +d\mathbf {u} \\\end{aligned}},}

where du{\displaystyle \mathbf {du} } is the relative displacement vector, which represents the relative displacement of Q{\displaystyle Q} with respect to P{\displaystyle P} in the deformed configuration.

Taylor approximation

For an infinitesimal element dX{\displaystyle d\mathbf {X} \,\!}, and assuming continuity on the displacement field, it is possible to use a Taylor series expansion around point P{\displaystyle P\,\!}, neglecting higher-order terms, to approximate the components of the relative displacement vector for the neighboring particle Q{\displaystyle Q} as u(X+dX)=u(X)+duorui=ui+duiu(X)+XudXoruiui+uiXJdXJ.{\displaystyle {\begin{aligned}\mathbf {u} (\mathbf {X} +d\mathbf {X} )&=\mathbf {u} (\mathbf {X} )+d\mathbf {u} \quad &{\text{or}}&\quad u_{i}^{*}=u_{i}+du_{i}\\&\approx \mathbf {u} (\mathbf {X} )+\nabla _{\mathbf {X} }\mathbf {u} \cdot d\mathbf {X} \quad &{\text{or}}&\quad u_{i}^{*}\approx u_{i}+{\frac {\partial u_{i}}{\partial X_{J}}}dX_{J}\,.\end{aligned}}} Thus, the previous equation dx=dX+du{\displaystyle d\mathbf {x} =d\mathbf {X} +d\mathbf {u} } can be written as dx=dX+du=dX+XudX=(I+Xu)dX=FdX{\displaystyle {\begin{aligned}d\mathbf {x} &=d\mathbf {X} +d\mathbf {u} \\&=d\mathbf {X} +\nabla _{\mathbf {X} }\mathbf {u} \cdot d\mathbf {X} \\&=\left(\mathbf {I} +\nabla _{\mathbf {X} }\mathbf {u} \right)d\mathbf {X} \\&=\mathbf {F} d\mathbf {X} \end{aligned}}}

Time-derivative of the deformation gradient

Calculations that involve the time-dependent deformation of a body often require a time derivative of the deformation gradient to be calculated. A geometrically consistent definition of such a derivative requires an excursion into differential geometry[1] but we avoid those issues in this article.

The time derivative of F{\displaystyle \mathbf {F} } is F˙=Ft=t[x(X,t)X]=X[x(X,t)t]=X[V(X,t)]{\displaystyle {\dot {\mathbf {F} }}={\frac {\partial \mathbf {F} }{\partial t}}={\frac {\partial }{\partial t}}\left[{\frac {\partial \mathbf {x} (\mathbf {X} ,t)}{\partial \mathbf {X} }}\right]={\frac {\partial }{\partial \mathbf {X} }}\left[{\frac {\partial \mathbf {x} (\mathbf {X} ,t)}{\partial t}}\right]={\frac {\partial }{\partial \mathbf {X} }}\left[\mathbf {V} (\mathbf {X} ,t)\right]} where V{\displaystyle \mathbf {V} } is the (material) velocity. The derivative on the right hand side represents a material velocity gradient. It is common to convert that into a spatial gradient by applying the chain rule for derivatives, i.e., F˙=X[V(X,t)]=X[v(x(X,t),t)]=x[v(x,t)]|x=x(X,t)x(X,t)X=lF{\displaystyle {\dot {\mathbf {F} }}={\frac {\partial }{\partial \mathbf {X} }}\left[\mathbf {V} (\mathbf {X} ,t)\right]={\frac {\partial }{\partial \mathbf {X} }}\left[\mathbf {v} (\mathbf {x} (\mathbf {X} ,t),t)\right]=\left.{\frac {\partial }{\partial \mathbf {x} }}\left[\mathbf {v} (\mathbf {x} ,t)\right]\right|_{\mathbf {x} =\mathbf {x} (\mathbf {X} ,t)}\cdot {\frac {\partial \mathbf {x} (\mathbf {X} ,t)}{\partial \mathbf {X} }}={\boldsymbol {l}}\cdot \mathbf {F} } where l=(xv)T{\displaystyle {\boldsymbol {l}}=(\nabla _{\mathbf {x} }\mathbf {v} )^{T}} is the spatial velocity gradient and where v(x,t)=V(X,t){\displaystyle \mathbf {v} (\mathbf {x} ,t)=\mathbf {V} (\mathbf {X} ,t)} is the spatial (Eulerian) velocity at x=x(X,t){\displaystyle \mathbf {x} =\mathbf {x} (\mathbf {X} ,t)}. If the spatial velocity gradient is constant in time, the above equation can be solved exactly to give F=elt{\displaystyle \mathbf {F} =e^{{\boldsymbol {l}}\,t}} assuming F=1{\displaystyle \mathbf {F} =\mathbf {1} } at t=0{\displaystyle t=0}. There are several methods of computing the exponential above.

Related quantities often used in continuum mechanics are the rate of deformation tensor and the spin tensor defined, respectively, as: d=12(l+lT),  w=12(llT).{\displaystyle {\boldsymbol {d}}={\tfrac {1}{2}}\left({\boldsymbol {l}}+{\boldsymbol {l}}^{T}\right)\,,~~{\boldsymbol {w}}={\tfrac {1}{2}}\left({\boldsymbol {l}}-{\boldsymbol {l}}^{T}\right)\,.} The rate of deformation tensor gives the rate of stretching of line elements while the spin tensor indicates the rate of rotation or vorticity of the motion.

The material time derivative of the inverse of the deformation gradient (keeping the reference configuration fixed) is often required in analyses that involve finite strains. This derivative is t(F1)=F1F˙F1.{\displaystyle {\frac {\partial }{\partial t}}\left(\mathbf {F} ^{-1}\right)=-\mathbf {F} ^{-1}\cdot {\dot {\mathbf {F} }}\cdot \mathbf {F} ^{-1}\,.} The above relation can be verified by taking the material time derivative of F1dx=dX{\displaystyle \mathbf {F} ^{-1}\cdot d\mathbf {x} =d\mathbf {X} } and noting that X˙=0{\displaystyle {\dot {\mathbf {X} }}=0}.

Polar decomposition of the deformation gradient tensor

Figure 3. Representation of the polar decomposition of the deformation gradient.

The deformation gradient F{\displaystyle \mathbf {F} }, like any invertible second-order tensor, can be decomposed, using the polar decomposition theorem, into a product of two second-order tensors (Truesdell and Noll, 1965): an orthogonal tensor and a positive definite symmetric tensor, i.e., F=RU=VR{\displaystyle \mathbf {F} =\mathbf {R} \mathbf {U} =\mathbf {V} \mathbf {R} } where the tensor R{\displaystyle \mathbf {R} } is a proper orthogonal tensor, i.e., R1=RT{\displaystyle \mathbf {R} ^{-1}=\mathbf {R} ^{T}} and detR=+1{\displaystyle \det \mathbf {R} =+1\,\!}, representing a rotation; the tensor U{\displaystyle \mathbf {U} } is the right stretch tensor; and V{\displaystyle \mathbf {V} } the left stretch tensor. The terms right and left means that they are to the right and left of the rotation tensor R{\displaystyle \mathbf {R} \,\!}, respectively. U{\displaystyle \mathbf {U} } and V{\displaystyle \mathbf {V} } are both positive definite, i.e. xUx>0{\displaystyle \mathbf {x} \cdot \mathbf {U} \cdot \mathbf {x} >0} and xVx>0{\displaystyle \mathbf {x} \cdot \mathbf {V} \cdot \mathbf {x} >0} for all non-zero xR3{\displaystyle \mathbf {x} \in \mathbb {R} ^{3}}, and symmetric tensors, i.e. U=UT{\displaystyle \mathbf {U} =\mathbf {U} ^{T}} and V=VT{\displaystyle \mathbf {V} =\mathbf {V} ^{T}\,\!}, of second order.

This decomposition implies that the deformation of a line element dX{\displaystyle d\mathbf {X} } in the undeformed configuration onto dx{\displaystyle d\mathbf {x} } in the deformed configuration, i.e., dx=FdX{\displaystyle d\mathbf {x} =\mathbf {F} \,d\mathbf {X} \,\!}, may be obtained either by first stretching the element by U{\displaystyle \mathbf {U} \,\!}, i.e. dx=UdX{\displaystyle d\mathbf {x} '=\mathbf {U} \,d\mathbf {X} \,\!}, followed by a rotation R{\displaystyle \mathbf {R} \,\!}, i.e., dx=Rdx{\displaystyle d\mathbf {x} =\mathbf {R} \,d\mathbf {x} '\,\!}; or equivalently, by applying a rigid rotation R{\displaystyle \mathbf {R} } first, i.e., dx=RdX{\displaystyle d\mathbf {x} '=\mathbf {R} \,d\mathbf {X} \,\!}, followed later by a stretching V{\displaystyle \mathbf {V} \,\!}, i.e., dx=Vdx{\displaystyle d\mathbf {x} =\mathbf {V} \,d\mathbf {x} '} (See Figure 3).

Due to the orthogonality of R{\displaystyle \mathbf {R} }V=RURT{\displaystyle \mathbf {V} =\mathbf {R} \cdot \mathbf {U} \cdot \mathbf {R} ^{T}} so that U{\displaystyle \mathbf {U} } and V{\displaystyle \mathbf {V} } have the same eigenvalues or principal stretches, but different eigenvectors or principal directionsNi{\displaystyle \mathbf {N} _{i}} and ni{\displaystyle \mathbf {n} _{i}\,\!}, respectively. The principal directions are related by ni=RNi.{\displaystyle \mathbf {n} _{i}=\mathbf {R} \mathbf {N} _{i}.}

This polar decomposition, which is unique as F{\displaystyle \mathbf {F} } is invertible with a positive determinant, is a corollary of the singular-value decomposition.

Transformation of a surface and volume element

To transform quantities that are defined with respect to areas in a deformed configuration to those relative to areas in a reference configuration, and vice versa, we use Nanson's relation, expressed as da n=J dA FTN{\displaystyle da~\mathbf {n} =J~dA~\mathbf {F} ^{-T}\cdot \mathbf {N} } where da{\displaystyle da} is an area of a region in the deformed configuration, dA{\displaystyle dA} is the same area in the reference configuration, and n{\displaystyle \mathbf {n} } is the outward normal to the area element in the current configuration while N{\displaystyle \mathbf {N} } is the outward normal in the reference configuration, F{\displaystyle \mathbf {F} } is the deformation gradient, and J=detF{\displaystyle J=\det \mathbf {F} \,\!}.

The corresponding formula for the transformation of the volume element is dv=J dV{\displaystyle dv=J~dV}

Derivation of Nanson's relation (see also [2])

To see how this formula is derived, we start with the oriented area elements in the reference and current configurations: dA=dA N ;  da=da n{\displaystyle d\mathbf {A} =dA~\mathbf {N} ~;~~d\mathbf {a} =da~\mathbf {n} } The reference and current volumes of an element are dV=dATdL ;  dv=daTdl{\displaystyle dV=d\mathbf {A} ^{T}\cdot d\mathbf {L} ~;~~dv=d\mathbf {a} ^{T}\cdot d\mathbf {l} } where dl=FdL{\displaystyle d\mathbf {l} =\mathbf {F} \cdot d\mathbf {L} \,\!}.

Therefore, daTdl=dv=J dV=J dATdL{\displaystyle d\mathbf {a} ^{T}\cdot d\mathbf {l} =dv=J~dV=J~d\mathbf {A} ^{T}\cdot d\mathbf {L} } or, daTFdL=dv=J dV=J dATdL{\displaystyle d\mathbf {a} ^{T}\cdot \mathbf {F} \cdot d\mathbf {L} =dv=J~dV=J~d\mathbf {A} ^{T}\cdot d\mathbf {L} } so, daTF=J dAT{\displaystyle d\mathbf {a} ^{T}\cdot \mathbf {F} =J~d\mathbf {A} ^{T}} So we get da=J FTdA{\displaystyle d\mathbf {a} =J~\mathbf {F} ^{-T}\cdot d\mathbf {A} } or, da n=J dA FTN{\displaystyle da~\mathbf {n} =J~dA~\mathbf {F} ^{-T}\cdot \mathbf {N} }Q.E.D.

Fundamental strain tensors

A strain tensor is defined by the IUPAC as:[3]

"A symmetric tensor that results when a deformation gradient tensor is factorized into a rotation tensor followed or preceded by a symmetric tensor".

Since a pure rotation should not induce any strains in a deformable body, it is often convenient to use rotation-independent measures of deformation in continuum mechanics. As a rotation followed by its inverse rotation leads to no change (RRT=RTR=I{\displaystyle \mathbf {R} \mathbf {R} ^{T}=\mathbf {R} ^{T}\mathbf {R} =\mathbf {I} \,\!}) we can exclude the rotation by multiplying the deformation gradient tensor F{\displaystyle \mathbf {F} } by its transpose.

Several rotation-independent deformation gradient tensors (or "deformation tensors", for short) are used in mechanics. In solid mechanics, the most popular of these are the right and left Cauchy–Green deformation tensors.

Cauchy strain tensor (right Cauchy–Green deformation tensor)

In 1839, George Green introduced a deformation tensor known as the right Cauchy–Green deformation tensor or Green's deformation tensor (the IUPAC recommends that this tensor be called the Cauchy strain tensor),[3] defined as:

C=FTF=U2orCIJ=FkI FkJ=xkXIxkXJ.{\displaystyle \mathbf {C} =\mathbf {F} ^{T}\mathbf {F} =\mathbf {U} ^{2}\qquad {\text{or}}\qquad C_{IJ}=F_{kI}~F_{kJ}={\frac {\partial x_{k}}{\partial X_{I}}}{\frac {\partial x_{k}}{\partial X_{J}}}.}

Physically, the Cauchy–Green tensor gives us the square of local change in distances due to deformation, i.e. dx2=dXCdX{\displaystyle d\mathbf {x} ^{2}=d\mathbf {X} \cdot \mathbf {C} \cdot d\mathbf {X} }

Invariants of C{\displaystyle \mathbf {C} } are often used in the expressions for strain energy density functions. The most commonly used invariants are I1C:=tr(C)=CII=λ12+λ22+λ32I2C:=12[(tr C)2tr(C2)]=12[(CJJ)2CIKCKI]=λ12λ22+λ22λ32+λ32λ12I3C:=det(C)=J2=λ12λ22λ32.{\displaystyle {\begin{aligned}I_{1}^{C}&:={\text{tr}}(\mathbf {C} )=C_{II}=\lambda _{1}^{2}+\lambda _{2}^{2}+\lambda _{3}^{2}\\I_{2}^{C}&:={\tfrac {1}{2}}\left[({\text{tr}}~\mathbf {C} )^{2}-{\text{tr}}(\mathbf {C} ^{2})\right]={\tfrac {1}{2}}\left[(C_{JJ})^{2}-C_{IK}C_{KI}\right]=\lambda _{1}^{2}\lambda _{2}^{2}+\lambda _{2}^{2}\lambda _{3}^{2}+\lambda _{3}^{2}\lambda _{1}^{2}\\I_{3}^{C}&:=\det(\mathbf {C} )=J^{2}=\lambda _{1}^{2}\lambda _{2}^{2}\lambda _{3}^{2}.\end{aligned}}} where J:=detF{\displaystyle J:=\det \mathbf {F} } is the determinant of the deformation gradient F{\displaystyle \mathbf {F} } and λi{\displaystyle \lambda _{i}} are stretch ratios for the unit fibers that are initially oriented along the eigenvector directions of the right (reference) stretch tensor (these are not generally aligned with the three axis of the coordinate systems).

Finger strain tensor

The IUPAC recommends[3] that the inverse of the right Cauchy–Green deformation tensor (called the Cauchy strain tensor in that document), i. e., C1{\displaystyle \mathbf {C} ^{-1}}, be called the Finger strain tensor. However, that nomenclature is not universally accepted in applied mechanics.

f=C1=F1FTorfIJ=XIxkXJxk{\displaystyle \mathbf {f} =\mathbf {C} ^{-1}=\mathbf {F} ^{-1}\mathbf {F} ^{-T}\qquad {\text{or}}\qquad f_{IJ}={\frac {\partial X_{I}}{\partial x_{k}}}{\frac {\partial X_{J}}{\partial x_{k}}}}

Green strain tensor (left Cauchy–Green deformation tensor)

Reversing the order of multiplication in the formula for the right Cauchy-Green deformation tensor leads to the left Cauchy–Green deformation tensor which is defined as: B=FFT=V2orBij=xiXKxjXK{\displaystyle \mathbf {B} =\mathbf {F} \mathbf {F} ^{T}=\mathbf {V} ^{2}\qquad {\text{or}}\qquad B_{ij}={\frac {\partial x_{i}}{\partial X_{K}}}{\frac {\partial x_{j}}{\partial X_{K}}}}

The left Cauchy–Green deformation tensor is often called the Finger deformation tensor, named after Josef Finger (1894).[4]

The IUPAC recommends that this tensor be called the Green strain tensor.[3]

Invariants of B{\displaystyle \mathbf {B} } are also used in the expressions for strain energy density functions. The conventional invariants are defined as I1:=tr(B)=Bii=λ12+λ22+λ32I2:=12[(tr B)2tr(B2)]=12(Bii2BjkBkj)=λ12λ22+λ22λ32+λ32λ12I3:=detB=J2=λ12λ22λ32{\displaystyle {\begin{aligned}I_{1}&:={\text{tr}}(\mathbf {B} )=B_{ii}=\lambda _{1}^{2}+\lambda _{2}^{2}+\lambda _{3}^{2}\\I_{2}&:={\tfrac {1}{2}}\left[({\text{tr}}~\mathbf {B} )^{2}-{\text{tr}}(\mathbf {B} ^{2})\right]={\tfrac {1}{2}}\left(B_{ii}^{2}-B_{jk}B_{kj}\right)=\lambda _{1}^{2}\lambda _{2}^{2}+\lambda _{2}^{2}\lambda _{3}^{2}+\lambda _{3}^{2}\lambda _{1}^{2}\\I_{3}&:=\det \mathbf {B} =J^{2}=\lambda _{1}^{2}\lambda _{2}^{2}\lambda _{3}^{2}\end{aligned}}} where J:=detF{\displaystyle J:=\det \mathbf {F} } is the determinant of the deformation gradient.

For compressible materials, a slightly different set of invariants is used: (I¯1:=J2/3I1 ;  I¯2:=J4/3I2 ;  J1) .{\displaystyle ({\bar {I}}_{1}:=J^{-2/3}I_{1}~;~~{\bar {I}}_{2}:=J^{-4/3}I_{2}~;~~J\neq 1)~.}

Piola strain tensor (Cauchy deformation tensor)

Earlier in 1828,[5]Augustin-Louis Cauchy introduced a deformation tensor defined as the inverse of the left Cauchy–Green deformation tensor, B1{\displaystyle \mathbf {B} ^{-1}\,\!}. This tensor has also been called the Piola strain tensor by the IUPAC[3] and the Finger tensor[6] in the rheology and fluid dynamics literature.

c=B1=F1TF1orcij=XKxiXKxj{\displaystyle \mathbf {c} =\mathbf {B} ^{-1}=\mathbf {F} ^{-1T}\mathbf {F} ^{-1}\qquad {\text{or}}\qquad c_{ij}={\frac {\partial X_{K}}{\partial x_{i}}}{\frac {\partial X_{K}}{\partial x_{j}}}}

Spectral representation

If there are three distinct principal stretches λi{\displaystyle \lambda _{i}\,\!}, the spectral decompositions of C{\displaystyle \mathbf {C} } and B{\displaystyle \mathbf {B} } is given by

C=i=13λi2NiNiandB=i=13λi2nini{\displaystyle \mathbf {C} =\sum _{i=1}^{3}\lambda _{i}^{2}\mathbf {N} _{i}\otimes \mathbf {N} _{i}\qquad {\text{and}}\qquad \mathbf {B} =\sum _{i=1}^{3}\lambda _{i}^{2}\mathbf {n} _{i}\otimes \mathbf {n} _{i}}

Furthermore,

U=i=13λiNiNi ;  V=i=13λinini{\displaystyle \mathbf {U} =\sum _{i=1}^{3}\lambda _{i}\mathbf {N} _{i}\otimes \mathbf {N} _{i}~;~~\mathbf {V} =\sum _{i=1}^{3}\lambda _{i}\mathbf {n} _{i}\otimes \mathbf {n} _{i}}R=i=13niNi ;  F=i=13λiniNi{\displaystyle \mathbf {R} =\sum _{i=1}^{3}\mathbf {n} _{i}\otimes \mathbf {N} _{i}~;~~\mathbf {F} =\sum _{i=1}^{3}\lambda _{i}\mathbf {n} _{i}\otimes \mathbf {N} _{i}}

Observe that V=R U RT=i=13λi R (NiNi) RT=i=13λi (R Ni)(R Ni){\displaystyle \mathbf {V} =\mathbf {R} ~\mathbf {U} ~\mathbf {R} ^{T}=\sum _{i=1}^{3}\lambda _{i}~\mathbf {R} ~(\mathbf {N} _{i}\otimes \mathbf {N} _{i})~\mathbf {R} ^{T}=\sum _{i=1}^{3}\lambda _{i}~(\mathbf {R} ~\mathbf {N} _{i})\otimes (\mathbf {R} ~\mathbf {N} _{i})} Therefore, the uniqueness of the spectral decomposition also implies that ni=R Ni{\displaystyle \mathbf {n} _{i}=\mathbf {R} ~\mathbf {N} _{i}\,\!}. The left stretch (V{\displaystyle \mathbf {V} \,\!}) is also called the spatial stretch tensor while the right stretch (U{\displaystyle \mathbf {U} \,\!}) is called the material stretch tensor.

The effect of F{\displaystyle \mathbf {F} } acting on Ni{\displaystyle \mathbf {N} _{i}} is to stretch the vector by λi{\displaystyle \lambda _{i}} and to rotate it to the new orientation ni{\displaystyle \mathbf {n} _{i}\,\!}, i.e., F Ni=λi (R Ni)=λi ni{\displaystyle \mathbf {F} ~\mathbf {N} _{i}=\lambda _{i}~(\mathbf {R} ~\mathbf {N} _{i})=\lambda _{i}~\mathbf {n} _{i}} In a similar vein, FT Ni=1λi ni ;  FT ni=λi Ni ;  F1 ni=1λi Ni .{\displaystyle \mathbf {F} ^{-T}~\mathbf {N} _{i}={\cfrac {1}{\lambda _{i}}}~\mathbf {n} _{i}~;~~\mathbf {F} ^{T}~\mathbf {n} _{i}=\lambda _{i}~\mathbf {N} _{i}~;~~\mathbf {F} ^{-1}~\mathbf {n} _{i}={\cfrac {1}{\lambda _{i}}}~\mathbf {N} _{i}~.}

Examples

Uniaxial extension of an incompressible material
This is the case where a specimen is stretched in 1-direction with a stretch ratio of α=α1{\displaystyle \mathbf {\alpha =\alpha _{1}} \,\!}. If the volume remains constant, the contraction in the other two directions is such that α1α2α3=1{\displaystyle \mathbf {\alpha _{1}\alpha _{2}\alpha _{3}=1} } or α2=α3=α0.5{\displaystyle \mathbf {\alpha _{2}=\alpha _{3}=\alpha ^{-0.5}} \,\!}. Then: F=[α000α0.5000α0.5]{\displaystyle \mathbf {F} ={\begin{bmatrix}\alpha &0&0\\0&\alpha ^{-0.5}&0\\0&0&\alpha ^{-0.5}\end{bmatrix}}}B=C=[α2000α1000α1]{\displaystyle \mathbf {B} =\mathbf {C} ={\begin{bmatrix}\alpha ^{2}&0&0\\0&\alpha ^{-1}&0\\0&0&\alpha ^{-1}\end{bmatrix}}}
Simple shear
F=[1γ0010001]{\displaystyle \mathbf {F} ={\begin{bmatrix}1&\gamma &0\\0&1&0\\0&0&1\end{bmatrix}}}B=[1+γ2γ0γ10001]{\displaystyle \mathbf {B} ={\begin{bmatrix}1+\gamma ^{2}&\gamma &0\\\gamma &1&0\\0&0&1\end{bmatrix}}}C=[1γ0γ1+γ20001]{\displaystyle \mathbf {C} ={\begin{bmatrix}1&\gamma &0\\\gamma &1+\gamma ^{2}&0\\0&0&1\end{bmatrix}}}
Rigid body rotation
F=[cosθsinθ0sinθcosθ0001]{\displaystyle \mathbf {F} ={\begin{bmatrix}\cos \theta &\sin \theta &0\\-\sin \theta &\cos \theta &0\\0&0&1\end{bmatrix}}}B=C=[100010001]=1{\displaystyle \mathbf {B} =\mathbf {C} ={\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}}=\mathbf {1} }

Derivatives of stretch

Derivatives of the stretch with respect to the right Cauchy–Green deformation tensor are used to derive the stress-strain relations of many solids, particularly hyperelastic materials. These derivatives are λiC=12λi NiNi=12λi RT (nini) R ;  i=1,2,3{\displaystyle {\cfrac {\partial \lambda _{i}}{\partial \mathbf {C} }}={\cfrac {1}{2\lambda _{i}}}~\mathbf {N} _{i}\otimes \mathbf {N} _{i}={\cfrac {1}{2\lambda _{i}}}~\mathbf {R} ^{T}~(\mathbf {n} _{i}\otimes \mathbf {n} _{i})~\mathbf {R} ~;~~i=1,2,3} and follow from the observations that C:(NiNi)=λi2 ;    CC=I(s) ;    I(s):(NiNi)=NiNi.{\displaystyle \mathbf {C} :(\mathbf {N} _{i}\otimes \mathbf {N} _{i})=\lambda _{i}^{2}~;~~~~{\cfrac {\partial \mathbf {C} }{\partial \mathbf {C} }}={\mathsf {I}}^{(s)}~;~~~~{\mathsf {I}}^{(s)}:(\mathbf {N} _{i}\otimes \mathbf {N} _{i})=\mathbf {N} _{i}\otimes \mathbf {N} _{i}.}

Physical interpretation of deformation tensors

Let X=Xi Ei{\displaystyle \mathbf {X} =X^{i}~{\boldsymbol {E}}_{i}} be a Cartesian coordinate system defined on the undeformed body and let x=xi Ei{\displaystyle \mathbf {x} =x^{i}~{\boldsymbol {E}}_{i}} be another system defined on the deformed body. Let a curve X(s){\displaystyle \mathbf {X} (s)} in the undeformed body be parametrized using s[0,1]{\displaystyle s\in [0,1]}. Its image in the deformed body is x(X(s)){\displaystyle \mathbf {x} (\mathbf {X} (s))}.

The undeformed length of the curve is given by lX=01|dXds| ds=01dXdsdXds ds=01dXdsIdXds ds{\displaystyle l_{X}=\int _{0}^{1}\left|{\cfrac {d\mathbf {X} }{ds}}\right|~ds=\int _{0}^{1}{\sqrt {{\cfrac {d\mathbf {X} }{ds}}\cdot {\cfrac {d\mathbf {X} }{ds}}}}~ds=\int _{0}^{1}{\sqrt {{\cfrac {d\mathbf {X} }{ds}}\cdot {\boldsymbol {I}}\cdot {\cfrac {d\mathbf {X} }{ds}}}}~ds} After deformation, the length becomes lx=01|dxds| ds=01dxdsdxds ds=01(dxdXdXds)(dxdXdXds) ds=01dXds[(dxdX)TdxdX]dXds ds{\displaystyle {\begin{aligned}l_{x}&=\int _{0}^{1}\left|{\cfrac {d\mathbf {x} }{ds}}\right|~ds=\int _{0}^{1}{\sqrt {{\cfrac {d\mathbf {x} }{ds}}\cdot {\cfrac {d\mathbf {x} }{ds}}}}~ds=\int _{0}^{1}{\sqrt {\left({\cfrac {d\mathbf {x} }{d\mathbf {X} }}\cdot {\cfrac {d\mathbf {X} }{ds}}\right)\cdot \left({\cfrac {d\mathbf {x} }{d\mathbf {X} }}\cdot {\cfrac {d\mathbf {X} }{ds}}\right)}}~ds\\&=\int _{0}^{1}{\sqrt {{\cfrac {d\mathbf {X} }{ds}}\cdot \left[\left({\cfrac {d\mathbf {x} }{d\mathbf {X} }}\right)^{T}\cdot {\cfrac {d\mathbf {x} }{d\mathbf {X} }}\right]\cdot {\cfrac {d\mathbf {X} }{ds}}}}~ds\end{aligned}}} Note that the right Cauchy–Green deformation tensor is defined as C:=FTF=(dxdX)TdxdX{\displaystyle {\boldsymbol {C}}:={\boldsymbol {F}}^{T}\cdot {\boldsymbol {F}}=\left({\cfrac {d\mathbf {x} }{d\mathbf {X} }}\right)^{T}\cdot {\cfrac {d\mathbf {x} }{d\mathbf {X} }}} Hence, lx=01dXdsCdXds ds{\displaystyle l_{x}=\int _{0}^{1}{\sqrt {{\cfrac {d\mathbf {X} }{ds}}\cdot {\boldsymbol {C}}\cdot {\cfrac {d\mathbf {X} }{ds}}}}~ds} which indicates that changes in length are characterized by C{\displaystyle {\boldsymbol {C}}}.

Finite strain tensors

The concept of strain is used to evaluate how much a given displacement differs locally from a rigid body displacement.[7][8][9] One of such strains for large deformations is the Lagrangian finite strain tensor, also called the Green-Lagrangian strain tensor or Green–St-Venant strain tensor, defined as

E=12(CI)orEKL=12(xjXKxjXLδKL){\displaystyle \mathbf {E} ={\frac {1}{2}}(\mathbf {C} -\mathbf {I} )\qquad {\text{or}}\qquad E_{KL}={\frac {1}{2}}\left({\frac {\partial x_{j}}{\partial X_{K}}}{\frac {\partial x_{j}}{\partial X_{L}}}-\delta _{KL}\right)}

or as a function of the displacement gradient tensor E=12[(Xu)T+Xu+(Xu)TXu]{\displaystyle \mathbf {E} ={\frac {1}{2}}\left[(\nabla _{\mathbf {X} }\mathbf {u} )^{T}+\nabla _{\mathbf {X} }\mathbf {u} +(\nabla _{\mathbf {X} }\mathbf {u} )^{T}\cdot \nabla _{\mathbf {X} }\mathbf {u} \right]} or EKL=12(uKXL+uLXK+uMXKuMXL){\displaystyle E_{KL}={\frac {1}{2}}\left({\frac {\partial u_{K}}{\partial X_{L}}}+{\frac {\partial u_{L}}{\partial X_{K}}}+{\frac {\partial u_{M}}{\partial X_{K}}}{\frac {\partial u_{M}}{\partial X_{L}}}\right)}

The Green-Lagrangian strain tensor is a measure of how much C{\displaystyle \mathbf {C} } differs from I{\displaystyle \mathbf {I} \,\!}.

The Eulerian finite strain tensor, or Eulerian-Almansi finite strain tensor, referenced to the deformed configuration (i.e. Eulerian description) is defined as

e=12(Ic)=12(IB1)orers=12(δrsXMxrXMxs){\displaystyle \mathbf {e} ={\frac {1}{2}}(\mathbf {I} -\mathbf {c} )={\frac {1}{2}}(\mathbf {I} -\mathbf {B} ^{-1})\qquad {\text{or}}\qquad e_{rs}={\frac {1}{2}}\left(\delta _{rs}-{\frac {\partial X_{M}}{\partial x_{r}}}{\frac {\partial X_{M}}{\partial x_{s}}}\right)}

or as a function of the displacement gradients we have eij=12(uixj+ujxiukxiukxj){\displaystyle e_{ij}={\frac {1}{2}}\left({\frac {\partial u_{i}}{\partial x_{j}}}+{\frac {\partial u_{j}}{\partial x_{i}}}-{\frac {\partial u_{k}}{\partial x_{i}}}{\frac {\partial u_{k}}{\partial x_{j}}}\right)}

Derivation of the Lagrangian and Eulerian finite strain tensors

A measure of deformation is the difference between the squares of the differential line element dX{\displaystyle d\mathbf {X} \,\!}, in the undeformed configuration, and dx{\displaystyle d\mathbf {x} \,\!}, in the deformed configuration (Figure 2). Deformation has occurred if the difference is non zero, otherwise a rigid-body displacement has occurred. Thus we have,

dx2dX2=dxdxdXdXor(dx)2(dX)2=dxjdxjdXMdXM{\displaystyle d\mathbf {x} ^{2}-d\mathbf {X} ^{2}=d\mathbf {x} \cdot d\mathbf {x} -d\mathbf {X} \cdot d\mathbf {X} \qquad {\text{or}}\qquad (dx)^{2}-(dX)^{2}=dx_{j}dx_{j}-dX_{M}\,dX_{M}}

In the Lagrangian description, using the material coordinates as the frame of reference, the linear transformation between the differential lines is

dx=xXdX=FdXordxj=xjXMdXM{\displaystyle d\mathbf {x} ={\frac {\partial \mathbf {x} }{\partial \mathbf {X} }}\,d\mathbf {X} =\mathbf {F} \,d\mathbf {X} \qquad {\text{or}}\qquad dx_{j}={\frac {\partial x_{j}}{\partial X_{M}}}\,dX_{M}}

Then we have,

dx2=dxdx=FdXFdX=dXFTFdX=dXCdXor(dx)2=dxjdxj=xjXKxjXLdXKdXL=CKLdXKdXL{\displaystyle {\begin{aligned}d\mathbf {x} ^{2}&=d\mathbf {x} \cdot d\mathbf {x} \\&=\mathbf {F} \cdot d\mathbf {X} \cdot \mathbf {F} \cdot d\mathbf {X} \\&=d\mathbf {X} \cdot \mathbf {F} ^{T}\mathbf {F} \cdot d\mathbf {X} \\&=d\mathbf {X} \cdot \mathbf {C} \cdot d\mathbf {X} \end{aligned}}\qquad {\text{or}}\qquad {\begin{aligned}(dx)^{2}&=dx_{j}\,dx_{j}\\&={\frac {\partial x_{j}}{\partial X_{K}}}{\frac {\partial x_{j}}{\partial X_{L}}}\,dX_{K}\,dX_{L}\\&=C_{KL}\,dX_{K}\,dX_{L}\\\end{aligned}}}

where CKL{\displaystyle C_{KL}} are the components of the right Cauchy–Green deformation tensor, C=FTF{\displaystyle \mathbf {C} =\mathbf {F} ^{T}\mathbf {F} \,\!}. Then, replacing this equation into the first equation we have,

dx2dX2=dXCdXdXdX=dX(CI)dX=dX2EdX{\displaystyle {\begin{aligned}d\mathbf {x} ^{2}-d\mathbf {X} ^{2}&=d\mathbf {X} \cdot \mathbf {C} \cdot d\mathbf {X} -d\mathbf {X} \cdot d\mathbf {X} \\&=d\mathbf {X} \cdot (\mathbf {C} -\mathbf {I} )\cdot d\mathbf {X} \\&=d\mathbf {X} \cdot 2\mathbf {E} \cdot d\mathbf {X} \\\end{aligned}}} or (dx)2(dX)2=xjXKxjXLdXKdXLdXMdXM=(xjXKxjXLδKL)dXKdXL=2EKLdXKdXL{\displaystyle {\begin{aligned}(dx)^{2}-(dX)^{2}&={\frac {\partial x_{j}}{\partial X_{K}}}{\frac {\partial x_{j}}{\partial X_{L}}}\,dX_{K}\,dX_{L}-dX_{M}\,dX_{M}\\&=\left({\frac {\partial x_{j}}{\partial X_{K}}}{\frac {\partial x_{j}}{\partial X_{L}}}-\delta _{KL}\right)\,dX_{K}\,dX_{L}\\&=2E_{KL}\,dX_{K}\,dX_{L}\end{aligned}}} where EKL{\displaystyle E_{KL}\,\!}, are the components of a second-order tensor called the Green – St-Venant strain tensor or the Lagrangian finite strain tensor, E=12(CI)orEKL=12(xjXKxjXLδKL){\displaystyle \mathbf {E} ={\frac {1}{2}}(\mathbf {C} -\mathbf {I} )\qquad {\text{or}}\qquad E_{KL}={\frac {1}{2}}\left({\frac {\partial x_{j}}{\partial X_{K}}}{\frac {\partial x_{j}}{\partial X_{L}}}-\delta _{KL}\right)}

In the Eulerian description, using the spatial coordinates as the frame of reference, the linear transformation between the differential lines is dX=Xxdx=F1dx=HdxordXM=XMxndxn{\displaystyle d\mathbf {X} ={\frac {\partial \mathbf {X} }{\partial \mathbf {x} }}d\mathbf {x} =\mathbf {F} ^{-1}\,d\mathbf {x} =\mathbf {H} \,d\mathbf {x} \qquad {\text{or}}\qquad dX_{M}={\frac {\partial X_{M}}{\partial x_{n}}}\,dx_{n}} where XMxn{\displaystyle {\frac {\partial X_{M}}{\partial x_{n}}}} are the components of the spatial deformation gradient tensor, H{\displaystyle \mathbf {H} \,\!}. Thus we have

dX2=dXdX=F1dxF1dx=dxFTF1dx=dxcdxor(dX)2=dXMdXM=XMxrXMxsdxrdxs=crsdxrdxs{\displaystyle {\begin{aligned}d\mathbf {X} ^{2}&=d\mathbf {X} \cdot d\mathbf {X} \\&=\mathbf {F} ^{-1}\cdot d\mathbf {x} \cdot \mathbf {F} ^{-1}\cdot d\mathbf {x} \\&=d\mathbf {x} \cdot \mathbf {F} ^{-T}\mathbf {F} ^{-1}\cdot d\mathbf {x} \\&=d\mathbf {x} \cdot \mathbf {c} \cdot d\mathbf {x} \end{aligned}}\qquad {\text{or}}\qquad {\begin{aligned}(dX)^{2}&=dX_{M}\,dX_{M}\\&={\frac {\partial X_{M}}{\partial x_{r}}}{\frac {\partial X_{M}}{\partial x_{s}}}\,dx_{r}\,dx_{s}\\&=c_{rs}\,dx_{r}\,dx_{s}\\\end{aligned}}} where the second order tensor crs{\displaystyle c_{rs}} is called Cauchy's deformation tensor, c=FTF1{\displaystyle \mathbf {c} =\mathbf {F} ^{-T}\mathbf {F} ^{-1}\,\!}. Then we have,

dx2dX2=dxdxdxcdx=dx(Ic)dx=dx2edx{\displaystyle {\begin{aligned}d\mathbf {x} ^{2}-d\mathbf {X} ^{2}&=d\mathbf {x} \cdot d\mathbf {x} -d\mathbf {x} \cdot \mathbf {c} \cdot d\mathbf {x} \\&=d\mathbf {x} \cdot (\mathbf {I} -\mathbf {c} )\cdot d\mathbf {x} \\&=d\mathbf {x} \cdot 2\mathbf {e} \cdot d\mathbf {x} \\\end{aligned}}} or (dx)2(dX)2=dxjdxjXMxrXMxsdxrdxs=(δrsXMxrXMxs)dxrdxs=2ersdxrdxs{\displaystyle {\begin{aligned}(dx)^{2}-(dX)^{2}&=dx_{j}\,dx_{j}-{\frac {\partial X_{M}}{\partial x_{r}}}{\frac {\partial X_{M}}{\partial x_{s}}}\,dx_{r}\,dx_{s}\\&=\left(\delta _{rs}-{\frac {\partial X_{M}}{\partial x_{r}}}{\frac {\partial X_{M}}{\partial x_{s}}}\right)\,dx_{r}\,dx_{s}\\&=2e_{rs}\,dx_{r}\,dx_{s}\end{aligned}}}

where ers{\displaystyle e_{rs}\,\!}, are the components of a second-order tensor called the Eulerian-Almansi finite strain tensor, e=12(Ic)orers=12(δrsXMxrXMxs){\displaystyle \mathbf {e} ={\frac {1}{2}}(\mathbf {I} -\mathbf {c} )\qquad {\text{or}}\qquad e_{rs}={\frac {1}{2}}\left(\delta _{rs}-{\frac {\partial X_{M}}{\partial x_{r}}}{\frac {\partial X_{M}}{\partial x_{s}}}\right)}

Both the Lagrangian and Eulerian finite strain tensors can be conveniently expressed in terms of the displacement gradient tensor. For the Lagrangian strain tensor, first we differentiate the displacement vector u(X,t){\displaystyle \mathbf {u} (\mathbf {X} ,t)} with respect to the material coordinates XM{\displaystyle X_{M}} to obtain the material displacement gradient tensor, Xu{\displaystyle \nabla _{\mathbf {X} }\mathbf {u} }

u(X,t)=x(X,t)XXu=FIF=Xu+Iorui=xiδiJXJδiJUJ=xiδiJXJxi=δiJ(UJ+XJ)xiXK=δiJ(UJXK+δJK)=uiXK+δiK{\displaystyle {\begin{aligned}\mathbf {u} (\mathbf {X} ,t)&=\mathbf {x} (\mathbf {X} ,t)-\mathbf {X} \\\nabla _{\mathbf {X} }\mathbf {u} &=\mathbf {F} -\mathbf {I} \\\mathbf {F} &=\nabla _{\mathbf {X} }\mathbf {u} +\mathbf {I} \\\end{aligned}}\qquad {\text{or}}\qquad {\begin{aligned}u_{i}&=x_{i}-\delta _{iJ}X_{J}\\\delta _{iJ}U_{J}&=x_{i}-\delta _{iJ}X_{J}\\x_{i}&=\delta _{iJ}\left(U_{J}+X_{J}\right)\\{\frac {\partial x_{i}}{\partial X_{K}}}&=\delta _{iJ}\left({\frac {\partial U_{J}}{\partial X_{K}}}+\delta _{JK}\right)\\&={\frac {\partial u_{i}}{\partial X_{K}}}+\delta _{iK}\end{aligned}}}

Replacing this equation into the expression for the Lagrangian finite strain tensor we have E=12(FTFI)=12[{(Xu)T+I}(Xu+I)I]=12[(Xu)T+Xu+(Xu)TXu]{\displaystyle {\begin{aligned}\mathbf {E} &={\frac {1}{2}}\left(\mathbf {F} ^{T}\mathbf {F} -\mathbf {I} \right)\\&={\frac {1}{2}}\left[\left\{(\nabla _{\mathbf {X} }\mathbf {u} )^{T}+\mathbf {I} \right\}\left(\nabla _{\mathbf {X} }\mathbf {u} +\mathbf {I} \right)-\mathbf {I} \right]\\&={\frac {1}{2}}\left[(\nabla _{\mathbf {X} }\mathbf {u} )^{T}+\nabla _{\mathbf {X} }\mathbf {u} +(\nabla _{\mathbf {X} }\mathbf {u} )^{T}\cdot \nabla _{\mathbf {X} }\mathbf {u} \right]\\\end{aligned}}} or EKL=12(xjXKxjXLδKL)=12[δjM(UMXK+δMK)δjN(UNXL+δNL)δKL]=12[δMN(UMXK+δMK)(UNXL+δNL)δKL]=12[(UMXK+δMK)(UMXL+δML)δKL]=12(UKXL+ULXK+UMXKUMXL){\displaystyle {\begin{aligned}E_{KL}&={\frac {1}{2}}\left({\frac {\partial x_{j}}{\partial X_{K}}}{\frac {\partial x_{j}}{\partial X_{L}}}-\delta _{KL}\right)\\&={\frac {1}{2}}\left[\delta _{jM}\left({\frac {\partial U_{M}}{\partial X_{K}}}+\delta _{MK}\right)\delta _{jN}\left({\frac {\partial U_{N}}{\partial X_{L}}}+\delta _{NL}\right)-\delta _{KL}\right]\\&={\frac {1}{2}}\left[\delta _{MN}\left({\frac {\partial U_{M}}{\partial X_{K}}}+\delta _{MK}\right)\left({\frac {\partial U_{N}}{\partial X_{L}}}+\delta _{NL}\right)-\delta _{KL}\right]\\&={\frac {1}{2}}\left[\left({\frac {\partial U_{M}}{\partial X_{K}}}+\delta _{MK}\right)\left({\frac {\partial U_{M}}{\partial X_{L}}}+\delta _{ML}\right)-\delta _{KL}\right]\\&={\frac {1}{2}}\left({\frac {\partial U_{K}}{\partial X_{L}}}+{\frac {\partial U_{L}}{\partial X_{K}}}+{\frac {\partial U_{M}}{\partial X_{K}}}{\frac {\partial U_{M}}{\partial X_{L}}}\right)\end{aligned}}}

Similarly, the Eulerian-Almansi finite strain tensor can be expressed as

eij=12(uixj+ujxiukxiukxj){\displaystyle e_{ij}={\frac {1}{2}}\left({\frac {\partial u_{i}}{\partial x_{j}}}+{\frac {\partial u_{j}}{\partial x_{i}}}-{\frac {\partial u_{k}}{\partial x_{i}}}{\frac {\partial u_{k}}{\partial x_{j}}}\right)}

Seth–Hill family of generalized strain tensors

B. R. Seth from the Indian Institute of Technology Kharagpur was the first to show that the Green and Almansi strain tensors are special cases of a more general strain measure.[10][11] The idea was further expanded upon by Rodney Hill in 1968.[12] The Seth–Hill family of strain measures (also called Doyle-Ericksen tensors)[13] can be expressed as

E(m)=12m(U2mI)=12m[CmI]{\displaystyle \mathbf {E} _{(m)}={\frac {1}{2m}}(\mathbf {U} ^{2m}-\mathbf {I} )={\frac {1}{2m}}\left[\mathbf {C} ^{m}-\mathbf {I} \right]}

For different values of m{\displaystyle m} we have:

  • Green-Lagrangian strain tensor E(1)=12(U2I)=12(CI){\displaystyle \mathbf {E} _{(1)}={\frac {1}{2}}(\mathbf {U} ^{2}-\mathbf {I} )={\frac {1}{2}}(\mathbf {C} -\mathbf {I} )}
  • Biot strain tensor E(1/2)=(UI)=C1/2I{\displaystyle \mathbf {E} _{(1/2)}=(\mathbf {U} -\mathbf {I} )=\mathbf {C} ^{1/2}-\mathbf {I} }
  • Logarithmic strain, Natural strain, True strain, or Hencky strain E(0)=lnU=12lnC{\displaystyle \mathbf {E} _{(0)}=\ln \mathbf {U} ={\frac {1}{2}}\,\ln \mathbf {C} }
  • Almansi strain E(1)=12[IU2]{\displaystyle \mathbf {E} _{(-1)}={\frac {1}{2}}\left[\mathbf {I} -\mathbf {U} ^{-2}\right]}

The second-order approximation of these tensors is E(m)=ε+12(u)Tu(1m)εTε{\displaystyle \mathbf {E} _{(m)}={\boldsymbol {\varepsilon }}+{\tfrac {1}{2}}(\nabla \mathbf {u} )^{T}\cdot \nabla \mathbf {u} -(1-m){\boldsymbol {\varepsilon }}^{T}\cdot {\boldsymbol {\varepsilon }}} where ε{\displaystyle {\boldsymbol {\varepsilon }}} is the infinitesimal strain tensor.

Many other different definitions of tensors E{\displaystyle \mathbf {E} } are admissible, provided that they all satisfy the conditions that:[14]

  • E{\displaystyle \mathbf {E} } vanishes for all rigid-body motions
  • the dependence of E{\displaystyle \mathbf {E} } on the displacement gradient tensor u{\displaystyle \nabla \mathbf {u} } is continuous, continuously differentiable and monotonic
  • it is also desired that E{\displaystyle \mathbf {E} } reduces to the infinitesimal strain tensor ε{\displaystyle {\boldsymbol {\varepsilon }}} as the norm |u|0{\displaystyle |\nabla \mathbf {u} |\to 0}

An example is the set of tensors E(n)=(UnUn)/2n{\displaystyle \mathbf {E} ^{(n)}=\left({\mathbf {U} }^{n}-{\mathbf {U} }^{-n}\right)/2n} which do not belong to the Seth–Hill class, but have the same 2nd-order approximation as the Seth–Hill measures at m=0{\displaystyle m=0} for any value of n{\displaystyle n}.[15]

Physical interpretation of the finite strain tensor

The diagonal components EKL{\displaystyle E_{KL}} of the Lagrangian finite strain tensor are related to the normal strain, e.g.

E11=e(I1)+12e(I1)2{\displaystyle E_{11}=e_{(\mathbf {I} _{1})}+{\frac {1}{2}}e_{(\mathbf {I} _{1})}^{2}}

where e(I1){\displaystyle e_{(\mathbf {I} _{1})}} is the normal strain or engineering strain in the direction I1{\displaystyle \mathbf {I} _{1}\,\!}.

The off-diagonal components EKL{\displaystyle E_{KL}} of the Lagrangian finite strain tensor are related to shear strain, e.g.

E12=122E11+12E22+1sinϕ12{\displaystyle E_{12}={\frac {1}{2}}{\sqrt {2E_{11}+1}}{\sqrt {2E_{22}+1}}\sin \phi _{12}}

where ϕ12{\displaystyle \phi _{12}} is the change in the angle between two line elements that were originally perpendicular with directions I1{\displaystyle \mathbf {I} _{1}} and I2{\displaystyle \mathbf {I} _{2}\,\!}, respectively.

Under certain circumstances, i.e. small displacements and small displacement rates, the components of the Lagrangian finite strain tensor may be approximated by the components of the infinitesimal strain tensor

Derivation of the physical interpretation of the Lagrangian and Eulerian finite strain tensors

The stretch ratio for the differential element dX=dXN{\displaystyle d\mathbf {X} =dX\mathbf {N} } (Figure) in the direction of the unit vector N{\displaystyle \mathbf {N} } at the material point P{\displaystyle P\,\!}, in the undeformed configuration, is defined as

Λ(N)=dxdX{\displaystyle \Lambda _{(\mathbf {N} )}={\frac {dx}{dX}}}

where dx{\displaystyle dx} is the deformed magnitude of the differential element dX{\displaystyle d\mathbf {X} \,\!}.

Similarly, the stretch ratio for the differential element dx=dxn{\displaystyle d\mathbf {x} =dx\mathbf {n} } (Figure), in the direction of the unit vector n{\displaystyle \mathbf {n} } at the material point p{\displaystyle p\,\!}, in the deformed configuration, is defined as 1Λ(n)=dXdx{\displaystyle {\frac {1}{\Lambda _{(\mathbf {n} )}}}={\frac {dX}{dx}}}

The square of the stretch ratio is defined as Λ(N)2=(dxdX)2{\displaystyle \Lambda _{(\mathbf {N} )}^{2}=\left({\frac {dx}{dX}}\right)^{2}}

Knowing that (dx)2=CKLdXKdXL{\displaystyle (dx)^{2}=C_{KL}dX_{K}dX_{L}} we have Λ(N)2=CKLNKNL{\displaystyle \Lambda _{(\mathbf {N} )}^{2}=C_{KL}N_{K}N_{L}} where NK{\displaystyle N_{K}} and NL{\displaystyle N_{L}} are unit vectors.

The normal strain or engineering strain eN{\displaystyle e_{\mathbf {N} }} in any direction N{\displaystyle \mathbf {N} } can be expressed as a function of the stretch ratio,

e(N)=dxdXdX=Λ(N)1{\displaystyle e_{(\mathbf {N} )}={\frac {dx-dX}{dX}}=\Lambda _{(\mathbf {N} )}-1}

Thus, the normal strain in the direction I1{\displaystyle \mathbf {I} _{1}} at the material point P{\displaystyle P} may be expressed in terms of the stretch ratio as

e(I1)=dx1dX1dX1=Λ(I1)1=C111=δ11+2E111=1+2E111{\displaystyle {\begin{aligned}e_{(\mathbf {I} _{1})}={\frac {dx_{1}-dX_{1}}{dX_{1}}}&=\Lambda _{(\mathbf {I} _{1})}-1\\&={\sqrt {C_{11}}}-1={\sqrt {\delta _{11}+2E_{11}}}-1\\&={\sqrt {1+2E_{11}}}-1\end{aligned}}}

solving for E11{\displaystyle E_{11}} we have

2E11=(dx1)2(dX1)2(dX1)2E11=(dx1dX1dX1)+12(dx1dX1dX1)2=e(I1)+12e(I1)2{\displaystyle {\begin{aligned}2E_{11}&={\frac {(dx_{1})^{2}-(dX_{1})^{2}}{(dX_{1})^{2}}}\\E_{11}&=\left({\frac {dx_{1}-dX_{1}}{dX_{1}}}\right)+{\frac {1}{2}}\left({\frac {dx_{1}-dX_{1}}{dX_{1}}}\right)^{2}\\&=e_{(\mathbf {I} _{1})}+{\frac {1}{2}}e_{(\mathbf {I} _{1})}^{2}\end{aligned}}}

The shear strain, or change in angle between two line elements dX1{\displaystyle d\mathbf {X} _{1}} and dX2{\displaystyle d\mathbf {X} _{2}} initially perpendicular, and oriented in the principal directions I1{\displaystyle \mathbf {I} _{1}} and I2{\displaystyle \mathbf {I} _{2}\,\!}, respectively, can also be expressed as a function of the stretch ratio. From the dot product between the deformed lines dx1{\displaystyle d\mathbf {x} _{1}} and dx2{\displaystyle d\mathbf {x} _{2}} we have

dx1dx2=dx1dx2cosθ12FdX1FdX2=dX1FTFdX1dX2FTFdX2cosθ12dX1FTFdX2dX1dX2=dX1FTFdX1dX2FTFdX2dX1dX2cosθ12I1CI2=ΛI1ΛI2cosθ12{\displaystyle {\begin{aligned}d\mathbf {x} _{1}\cdot d\mathbf {x} _{2}&=dx_{1}dx_{2}\cos \theta _{12}\\\mathbf {F} \cdot d\mathbf {X} _{1}\cdot \mathbf {F} \cdot d\mathbf {X} _{2}&={\sqrt {d\mathbf {X} _{1}\cdot \mathbf {F} ^{T}\cdot \mathbf {F} \cdot d\mathbf {X} _{1}}}\cdot {\sqrt {d\mathbf {X} _{2}\cdot \mathbf {F} ^{T}\cdot \mathbf {F} \cdot d\mathbf {X} _{2}}}\cos \theta _{12}\\{\frac {d\mathbf {X} _{1}\cdot \mathbf {F} ^{T}\cdot \mathbf {F} \cdot d\mathbf {X} _{2}}{dX_{1}dX_{2}}}&={\frac {{\sqrt {d\mathbf {X} _{1}\cdot \mathbf {F} ^{T}\cdot \mathbf {F} \cdot d\mathbf {X} _{1}}}\cdot {\sqrt {d\mathbf {X} _{2}\cdot \mathbf {F} ^{T}\cdot \mathbf {F} \cdot d\mathbf {X} _{2}}}}{dX_{1}dX_{2}}}\cos \theta _{12}\\\mathbf {I} _{1}\cdot \mathbf {C} \cdot \mathbf {I} _{2}&=\Lambda _{\mathbf {I} _{1}}\Lambda _{\mathbf {I} _{2}}\cos \theta _{12}\end{aligned}}}

where θ12{\displaystyle \theta _{12}} is the angle between the lines dx1{\displaystyle d\mathbf {x} _{1}} and dx2{\displaystyle d\mathbf {x} _{2}} in the deformed configuration. Defining ϕ12{\displaystyle \phi _{12}} as the shear strain or reduction in the angle between two line elements that were originally perpendicular, we have

ϕ12=π2θ12{\displaystyle \phi _{12}={\frac {\pi }{2}}-\theta _{12}} thus, cosθ12=sinϕ12{\displaystyle \cos \theta _{12}=\sin \phi _{12}} then I1CI2=ΛI1ΛI2sinϕ12{\displaystyle \mathbf {I} _{1}\cdot \mathbf {C} \cdot \mathbf {I} _{2}=\Lambda _{\mathbf {I} _{1}}\Lambda _{\mathbf {I} _{2}}\sin \phi _{12}}

or

C12=C11C22sinϕ122E12+δ12=2E11+12E22+1sinϕ12E12=122E11+12E22+1sinϕ12{\displaystyle {\begin{aligned}C_{12}&={\sqrt {C_{11}}}{\sqrt {C_{22}}}\sin \phi _{12}\\2E_{12}+\delta _{12}&={\sqrt {2E_{11}+1}}{\sqrt {2E_{22}+1}}\sin \phi _{12}\\E_{12}&={\frac {1}{2}}{\sqrt {2E_{11}+1}}{\sqrt {2E_{22}+1}}\sin \phi _{12}\end{aligned}}}

Compatibility conditions

The problem of compatibility in continuum mechanics involves the determination of allowable single-valued continuous fields on bodies. These allowable conditions leave the body without unphysical gaps or overlaps after a deformation. Most such conditions apply to simply-connected bodies. Additional conditions are required for the internal boundaries of multiply connected bodies.

Compatibility of the deformation gradient

The necessary and sufficient conditions for the existence of a compatible F{\displaystyle {\boldsymbol {F}}} field over a simply connected body are ×F=0{\displaystyle {\boldsymbol {\nabla }}\times {\boldsymbol {F}}={\boldsymbol {0}}}

Compatibility of the right Cauchy–Green deformation tensor

The necessary and sufficient conditions for the existence of a compatible C{\displaystyle {\boldsymbol {C}}} field over a simply connected body are Rαβργ:=Xρ[(X)Γαβγ]Xβ[(X)Γαργ]+(X)Γμργ(X)Γαβμ(X)Γμβγ(X)Γαρμ=0{\displaystyle R_{\alpha \beta \rho }^{\gamma }:={\frac {\partial }{\partial X^{\rho }}}[\,_{(X)}\Gamma _{\alpha \beta }^{\gamma }]-{\frac {\partial }{\partial X^{\beta }}}[\,_{(X)}\Gamma _{\alpha \rho }^{\gamma }]+\,_{(X)}\Gamma _{\mu \rho }^{\gamma }\,_{(X)}\Gamma _{\alpha \beta }^{\mu }-\,_{(X)}\Gamma _{\mu \beta }^{\gamma }\,_{(X)}\Gamma _{\alpha \rho }^{\mu }=0} We can show these are the mixed components of the Riemann–Christoffel curvature tensor. Therefore, the necessary conditions for C{\displaystyle {\boldsymbol {C}}}-compatibility are that the Riemann–Christoffel curvature of the deformation is zero.

Compatibility of the left Cauchy–Green deformation tensor

General sufficiency conditions for the left Cauchy–Green deformation tensor in three dimensions has been discussed in several works.[16]

See also

References

  1. A. Yavari, J.E. Marsden, and M. Ortiz, On spatial and material covariant balance laws in elasticity, Journal of Mathematical Physics, 47, 2006, 042903; pp. 1–53.
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Further reading